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How many molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium? 4Na + O2 -> 2Na2O A. 11.69 x 1023 molecules of Na2O

Respuesta :

Edufirst

Answer:

  • 7.04 × 10²⁴ molecules of Na₂O

Explanation:

1) Balanced chemical equation (given):

  • 4 Na(s) + O₂ (g) → 2Na₂O (s)

2) Mole ratio:

  • 1 mol O₂ : 2 mol Na₂O

3) Number of moles of O₂ in 187 grams of oxygen:

  • Molar mass O₂ = 32.00 g/mol

  • Number of moles = mass in grams / molar mass = 187 g / 32.00 g/mol = 5.844 mol

4) Number of moles of Na₂O:

  • Proportion: 1 mol O₂ / 2 mol Na₂O = 5.844 mol O₂ / x

  • x = 5.844 mol O₂ (2 mol Na₂O / 1 mol O₂) = 11.688 mol Na₂O

5) Number of molecules

  • Number of molecules = number of moles × Avogadro's number

  • Number of molecules = 11.688 mol × 6.022 × 10²³ molecules/mol =

                                               = 7.04 × 10 ²⁴ molecules ← answer

The answer is rounded to three significant figures.

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