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In the following combustion reaction of acetylene (C2H2), how many liters of CO2 will be produced if 60 liters of O2 is used, given that both gases are at STP?
2C2H2+5O2 2H2O+4CO2

The volume of one mole of gas at STP is 22.4 liters.

Respuesta :

2C₂H₂ + 5O₂ = 2H₂O + 4CO₂

V(O₂)=60 l
Vm=22.4 l/mol (the numeric value does not need)

V(O₂)/{5Vm}=V(CO₂)/{4Vm}

V(CO₂)=4V(O₂)/5

V(CO₂)=4*60/5=48 l

48  liters of CO₂ will be produced

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