Respuesta :

[tex]\sqrt{x+14}+2=x\\ \sqrt{x+14}=x-2\\ \sqrt{x+14}^2=(x-2)^2\\ x+14=x^2-4x+4\\ x+14-(x^2-4x+4)=0\\ -x^2+5x+10=0\\ x1,2=\frac{5+-\sqrt{65}}{2}[/tex]

insert both x solutions to see if they match the origional equation -> only [tex]\frac{5+\sqrt{65}}{2}[/tex] is correct

which is neither equal to -6 or 1 so it is "none of the above"

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