A circus acrobat is shot out of a cannon. The equation for the acrobat's pathway can be modeled by h= -16t^2+25. How long will it take him to reach the ground?
For this we almost have the following equation: [tex]h = -16t ^ 2 + 25
[/tex] We must match the equation to zero: [tex]-16t ^ 2 + 25 = 0
[/tex] From here, we clear the value of t. We have then: [tex]16t ^ 2 = 25
t ^ 2 = 25/16[/tex] We discard the negative root because we are looking for time: [tex]t = \sqrt{ \frac{25}{16} }
[/tex] [tex]t = \frac{5}{4} [/tex] Answer: it will take him to reach the ground about: [tex]t = \frac{5}{4} [/tex] seconds
